weight

4 Answers

62
Lokesh Verma ·

sankara.. this is not very very tough..

Hint:

you need to look at the fbd..

there will be acceleeration towards the center v2/r

the component in the vertical direction will give the weight fo the person!

So mg-v2/r cos θ

theta varies from 0 to 2pi

3
msp ·

sir is there any force due to the arm sir.

62
Lokesh Verma ·

yes .. but not on the wieghing machine..

see the weighting machine is on the floor.. (I am assuming this!)

It measures the normal reaction!

3
msp ·

i am rong with fbd sir.txxx for correcting me.

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