i am rong with fbd sir.txxx for correcting me.
4 Answers
Lokesh Verma
·2009-01-10 21:44:19
sankara.. this is not very very tough..
Hint:
you need to look at the fbd..
there will be acceleeration towards the center v2/r
the component in the vertical direction will give the weight fo the person!
So mg-v2/r cos θ
theta varies from 0 to 2pi
Lokesh Verma
·2009-01-10 21:56:44
yes .. but not on the wieghing machine..
see the weighting machine is on the floor.. (I am assuming this!)
It measures the normal reaction!