1nishant bhaiya...........I think u have entered some answer for some other question
A block of mass 50kg is released from the position of rest at which the spring is under a tension of 45N. Find the velocity of the block at a position when its displacement is 150mm.
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9find x using kx= mg
2Δxmg = (mv2 + kX2 - kx2)
Δx=150mm
X=400mm ( X = x +2Δx)
x=100mm
1i think we can find x by..........f=kx
i got x=0.1m
but wasn't clear with what to do next
1i want some one to check whether final answer is............1.22m/s
9ok i dint see that T =45
then apply my method with x=+ or - .1
ull get two ans