WORK POWER ENERGY

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#Physics #Mechanics

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62

Lokesh Verma ·2009-08-26 02:22:09

F=2x

m(dv/dx)(dx/dt)=2x
vdv=2xdx

v²/2=2x²/2

Thus, v=√2x

Your answer seems to be right to me too :)

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Basic Integral Calculus Operators Symbols Matrix Cases

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