New formula for IIT exam
OUR SPECIAL CORRESPONDENT
New Delhi, Oct. 19: When IIT aspirants sit for the joint entrance test next year, they will have the freedom to concentrate on questions of their choice and not worry about subject-wise performance.
The Joint Admission Board (JAB), which conducts the IIT-JEE, today decided to scrap the average formula and follow a new system for calculating the qualifying marks in the 2012 exam, expected to be taken by nearly six lakh candidates on April 8.
Under the earlier system, students had to secure a minimum qualifying mark in a subject, which was the average of marks of all candidates in that subject, and another aggregate qualifying mark, which was the average of the total marks of all candidates. Students who cleared both the average qualifying marks made it to the IIT-JEE list.
A rank, however, did not guarantee admission to an IIT because the premier tech schools have another cut-off system to select students from among the rank holders.
What the JAB did today was scrap the average formula for calculating the marks needed to qualify for the IIT-JEE list. General category candidates now must score at least 10 per cent in each subject and 35 per cent in aggregate to find a place on the common rank list.
“Earlier, a candidate was in the dark about what the minimum eligibility would be in a particular subject. Hence candidates were giving almost equal time to answer questions from mathematics, chemistry and physics to ensure that they did not score less than the average mark in the subject,†IIT-JEE chairman G.B. Reddy told The Telegraph.
“Now a candidate, after being assured of 10 per cent marks in a particular subject, can concentrate more on questions of his choice in other subjects and has the chance of scoring more. This will give more freedom to candidates.â€
Separate lists will be prepared for the Other Backward Classes, Scheduled Caste and Scheduled Tribe categories.
OBC candidates have to score at least 9 per cent in each subject and 31.5 per cent in aggregate to qualify for the OBC rank list, while SC/ST students must score at least 5 per cent in each subject and 17.5 per cent in aggregate to be on their respective rank lists.
The cut-off formula will then be used to select eligible students for admission in the IITs, ISM Dhanbad and IT-BHU.
Copying case
IIT Roorkee authorities have not filed an FIR even six months after mass copying was reported at a joint entrance examination centre in Punjab.
A team from the IITs had found that about 30 candidates were provided with copy materials during the April 10 JEE at a centre in Bhatinda, raising suspicions about a possible nexus between JEE authorities of IIT Roorkee — the centre comes under it — and those caught copying
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