13I think- A-True, R-False.
A:though light of a single frequncy (monochromatic) is incident on a metal,the energies of emmited photo elctrons may be diff
R:The energy of electrons emmited from inside metal surface is redistributed in collisons with other atoms in metal
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29I think the answer shud be A
Since photons are all carrying the same energy but the KE of the electrons emitted is different due to the collisions it make while coming out of the metal surface
24ans is a)
but how can reason be true ?????
i have read that no collisons within the metal b.w electrons is one of the assumptions while deriving photoelectric eqn..
otherwise there should be a term of loss of energy in eqn..
29Photoelectric Equation
hν = φ + KEmax
So there is no use of energy loss term....coz we are finding the KE of the photoelectron which is losely bound and didnt make any collisions..
24@govind..if it didnt make any collisons then how can reason be right ??
1The equation written by govind is correct according to which a single photon carries energy hv into the surface where it is absorbed by a single electron. Part of this energy W or φ is used in causing the electron to escape from the metal surface. the excess energy become KE. if the electron does not lose energy by internal collisions as it escapes from the metal, it will still have this much KE. Thus there is a scope of redistribution of energy and hence, energy of emitted photoelectron may be different. Hence, A (correct explaination)
