1
rajatjain_ix
·2010-02-15 08:14:07
1) w/c
2) 4/(3c)
r dese correct?
1
abcd
·2010-02-15 08:16:31
dude the answer is
W/2c
and
pi r^2 I/c
1
Jesh
·2010-02-15 08:16:47
@rajat ur both ans are wrong dude!!
1
Jesh
·2010-02-15 08:17:30
hey ishan u r right! but i want solutions !!
29
govind
·2010-02-17 05:13:24
Jesh in the first one completely reflecting means the change in momentum = 2c
in the second I.Ï€r2 = F.v ..
so F comes out to be I πr2 / c
1
Jesh
·2010-02-24 07:11:45
anyway i got the first two probs can u also try this!!
3) In a photo cell the plates P and Q have a separation of 10cm, which are connected through a galvanometer without any cell.Bichromatic light of wavelengths 4000 Ao and 6000 A0 are incident on plate Q whose work function is 2.39eV. If a uniform magnetic field B exists parallel to the plates, find the minimum value of B for which the galvanometer shows zero deflection.
13
Avik
·2010-02-24 08:00:05
Engy withrespective lights ::
4000A0 ,E=3.09 eV
6000A0 ,E=2.06eV
So, only the 4000A0 wavelength waali light wud be responsible fr ejecting the electrons.
MAx, KE of ejected e- = 3.09-2.39 = 0.7eV.
29
govind
·2010-02-24 08:05:26
The current will stop..use the relation r = mv/qB..
so wen the radius is less than 10cm the partcles will get deflected and will not reach the opposite plate..
btw the answer i am getting is B ≥ 2.8 * 10-5 T
13
Avik
·2010-02-24 08:07:29
Yeh, i was taking the mag. field perpendicular to the plates instead of parallel... :P, thnx.
1
radhika roy
·2010-05-02 21:18:53
A totally reflecting , small plane mirror placed horizontally faces a parallel beam of light. The mass of the mirror is 20g. Assume that there is no absorption in the lens and that 30% of the light emitted by the source goes through the lens. Find the power of the source needed to support The weight of the mirror. Take g=10m/s2
11
SANDIPAN CHAKRABORTY
·2010-05-04 23:40:54
Since the mirror is totally reflecting...
Prad = 2I/c (where I =intensity = power /unit area )
so 2 Ic x 30100 = mg
put all the values....
you get I = 108
1
radhika roy
·2010-05-04 23:48:40
OH !!!! THAT WAS EASY. . THANKS SANDIPAN . .