71Since ,we are neglecting the Inductance of the loop, the charge flown through the loop will be given by q = ∫ io dt
Now, q = ∫ io dt = 1R ∫ dφ = Δφ/R
So you need to calculate the change in flux Which is trivial task.
a square loop PQRS of side 'L' is placed near an infinite current( i ) carrying wire in the same plane at a distance 'L'. now the loop is rotated about side PS by 90° . find the charge which passes through any point of the loop during rotation.
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| S _____R
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| | |
| P ---------Q
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<---(L)---><---(L)--->
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5 Answers
71
1can v do it by alt current way
i= io(sin ωt)
which is equivalent to i calculated by vivek = -(dφ/dt)/R
and then equate and integrate maybe??....is it possible??
