Radioactivity-1

2 Answers

1057
Ketan Chandak ·

dN/dt=X-(lamda)N
number of radioactive nuclei will be constant when dN/dt is 0..

X=(lamda)N
N=X/(lamda)
lamda=ln2/Y
thus,N=XY/ln2.

so correct option is A.

1161
Akash Anand ·

Why you people are not participating in Physics forum?

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