dN/dt=X-(lamda)N
number of radioactive nuclei will be constant when dN/dt is 0..
X=(lamda)N
N=X/(lamda)
lamda=ln2/Y
thus,N=XY/ln2.
so correct option is A.
- Akash Anand Good Work :)Upvote·0· Reply ·2013-02-26 05:52:25
dN/dt=X-(lamda)N
number of radioactive nuclei will be constant when dN/dt is 0..
X=(lamda)N
N=X/(lamda)
lamda=ln2/Y
thus,N=XY/ln2.
so correct option is A.