3331/e
Akash Anand Good work :)
Try to give the solution at the day end.Upvote·0· Reply ·2013-02-26 23:54:06
4 Answers
661number of nuclei present at time t is given by
N=Noepower(-kt),No=number of nuclei present at t=0
one mean life 1/k
so at one mean life N=Noepower(-k*1/k)
=Noepower(-1)
probability=number of nuclei presen/total number of nuclei present at t=0
so probability=N/No=epower(-1)=1/e
333333@akash bhaiyya....i think u shud start a concept of the day section,where you discuss important concepts..for jee..i am sure its gonna be very helpful and then everybody will join the physics forum...plz shubh kaam mein deri mat kijiye...start nw..
- Hardik Sheth 3 months...90 concepts...plz start...
- Akash Anand Well ..directly saying concept actually wont work that much. It will get appreciated only it is given via a problem. Else it will be another book of formula ..nothing else.
And don't worry I am putting such questions to make your concepts crystal clear without saying is directly.
6611/e
- Akash Anand Good work :) Try to give the solution at the day end..any one of you who are providing the answers.