clearly x + y = 60° so, LCOD = 60° => LCOA = 120°
we just draw the angle bisector of COA meeting AC at M
so, ΔAOE ≡ ΔAOM and ΔCOM ≡ ΔCOD
Thus, AE = AM and CD = CM
or, AE + CD = AM + CM = AC
or, CD + AE = AC proved
.
clearly x + y = 60° so, LCOD = 60° => LCOA = 120°
we just draw the angle bisector of COA meeting AC at M
so, ΔAOE ≡ ΔAOM and ΔCOM ≡ ΔCOD
Thus, AE = AM and CD = CM
or, AE + CD = AM + CM = AC
or, CD + AE = AC proved
.