very short..but good

The product of the digits of a three-digit number is 105. What is the largest possible value of the number?

its a sitter....just about 2 lines..

9 Answers

1
Thedarkknight ·

I am not sure,but is it 735?

24
eureka123 ·

both of u r very close.......[5][5]

1
Philip Calvert ·

haha 753

1
Philip Calvert ·

dint see eureka s post !!

mani and dark knight [3][3] u got too excited !

24
eureka123 ·

yo philip.. bang on target.......

1
Philip Calvert ·

[6]

24
eureka123 ·

post ur method ...lets see if our method matches...

mine:
doing prime factorization of 105=3*5*7
=>Hundreds digit is 7 ,tens digit 5,ones digit 3
=> no. is 753

1
Philip Calvert ·

well i dont really think that needs to be done
because there is possibly just no other method to it
largest no is needed so immediately we place 7 the highest single digit no. that divides 105 ** at the hundreds place **

then the rest bcomes clear as we know 15 = 5*3

wow i tell u i suddenly like this question there is recursion visible !

24
eureka123 ·

well our methods are same then....but does any other method strike u????

and where is recursion here??
or am i not able to realize it??

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