1any one????
an object is placed in medium 1 of refractive index n1 and height h1,above that there is another medium of the refractive index n2and height h2. and( n2>n1). and there is air around them i.e. above medium 1 nd below medium 2. find the apperent height of the when viewed from air medium above medium 2
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6 Answers
3n1/h1 = n2/h
h = (n2*h1)/n1
n2/(h+h2) = 1/happ
happ = h+h2/n2
orr (n2h1+n1h2)/(n2)(n1) from the int betw medium 2 and air .....
1see the best method to solve these sums is to use the simple refraction through plane surfaces formuala i always get confused with apparent hieght so here
pls confirm the answers (hvnt revised for a long time)
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first u2/v-u1/u=u2-u1/r since plane surface r=infinity and the function i 0
so u2/v+u1/u=0 taking sgn convention....
n2/v=-1/h1
v=-n2/h1
now for the 2nd refraction .....
distance becomes n2/h1+h2.....
now again
n1/v=-n2/u as rays travel from n2-n1
v=un2/n1
an u is n2/h1 +h2