2√fg
- Akash Anand Wrong ..keep trying :)Upvote·0· Reply ·2013-02-28 22:09:20
- Soumyabrata Mondal speed of image w.r.t. mirror or object
2√fg
infinite?
Here is some hint for this question. This question is bit lengthy.
dvdt=-(v2u2)dudt
At any time t,
u =f-gt22
and v = (f+gt2)f(f-gt2)
Putting these values in equation we are going to get velocity of the image as a function of t.
vi=((f+gt2)4f(f-gt2)2)2(gt)
After that all you want to maximize it.
If any one have some other easier method ..plz post it.