Geometrical Optics-4

JEE Mains Preparation › Optics questions › Geometrical Optics-4

#Physics #Optics

UP 0 DOWN 0 0 6
Post on FacebookPost anonymously?

6 Answers

383

Soumyabrata Mondal ·2013-02-28 06:08:36

2√fg

UP 0 DOWN 2
Akash Anand Wrong ..keep trying :)
Upvote·0· Reply ·2013-02-28 22:09:20
Soumyabrata Mondal speed of image w.r.t. mirror or object
Upvote·0· Reply ·2013-03-01 00:52:23
Post on FacebookPost anonymously?

661

Gaurav Gardi ·2013-02-28 22:05:38

2âˆš(fg)

UP 0 DOWN 1
Akash Anand Wrong ..keep trying :)
Upvote·0· Reply ·2013-02-28 22:09:52
Post on FacebookPost anonymously?

333

Hardik Sheth ·2013-03-01 06:15:03

infinite?

UP 0 DOWN 2
Anurag Roy How can it be infinite???
Upvote·0· Reply ·2013-03-01 06:40:52
Hardik Sheth i dint see f/2
Upvote·0· Reply ·2013-03-01 06:43:53
Post on FacebookPost anonymously?

101

Anurag Roy ·2013-03-01 06:42:08

âˆšfg????

UP 0 DOWN 0
Post on FacebookPost anonymously?

1161

Akash Anand ·2013-03-01 22:19:21

Correct answer is 34√3fg

Now try one again.

UP 0 DOWN 1
Akash Anand *once
Upvote·0· Reply ·2013-03-02 00:55:25
Post on FacebookPost anonymously?

1161

Akash Anand ·2013-03-04 22:08:41

Here is some hint for this question. This question is bit lengthy.

dvdt=-(v²u²)dudt

At any time t,
u =f-gt²2
and v = (f+gt²)f(f-gt²)

Putting these values in equation we are going to get velocity of the image as a function of t.

v_i=((f+gt²)4f(f-gt²)²)²(gt)

After that all you want to maximize it.

If any one have some other easier method ..plz post it.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω