Dispersion = $v-$r=(nv-nr)×A
So dispersion =(1.50-1.48)×.4=.08 degree
Light of wavelength 4000 Ao is incident at small angle on a prism of apex angle 4o
The prism has nv = 1.5 & nr = 1.48.
The angle of dispersion produced by the prism in this light is ?
A)0.2o B) 0.08o C)0.192o D)None of these
Dispersion = $v-$r=(nv-nr)×A
So dispersion =(1.50-1.48)×.4=.08 degree