21PL. POST ur ans. here
15 Answers
21ya so we'll b using this : δm = 2i - A
r1 = r2 = A/2 =30°
sini = μsinr
NOW MY DBT IS WAT WILL U TAKE AS μ
**√3/2 or √2
11bhai μ hamesha 1 se bada hi to lete hai na [1][1][1]
so wats the point in asking[7]
130° ... ∂ = 2i - 60 , i = 45° since r is A / 2 = 30°
yaar the slab only displaces the ray .. does not change the angle of incidence ... u could keep the slab at a negligible distance from the prism .. then u could figure it out urself .. yaar ..
1no this is where the mistake lies I think , here the ray is entering from the √3 slab , and not from air . check out my picture
21Yeah!!! Sri I m in full support wid u!!!
That was precisely y i posted it........
but then I was not sure.........
The solution says wat ankit says in : post #9
1how's that possible ??? yahhan to √3 slab se light is going to prism na ??? [5][5][5][12][12] how please reasons needed . aap mughe dara rahe ho . please manish kyun aisa hota hai batiyenge plz ?
1357srinath your diagram is not for minimum deviation
it looks like for maximum deviation
1srinath u have calculated the angle of deviation for grazing incidence ... this is not same as angle of min. deviation !!