3for the 13th one
n/t=3.2x10-2/5x1.6x10-19
no of photons emitted per second=4x1016
and for 106 photons 1 photoelectron is emitted
and so the total no of the photoelectrons=4x1010
but it is not in the option can any one pls reply were i went rong
In a photoelectric effect setup , a point source of light of power 3.2*10^-2 W emits mono energetic photons of energy 5.0ev.The source is located at a distance of .8m from the center of a stationary metallic sphere of work function 3.0eV and of radius 8.0*10-3m The efficiency of photo electron emission is one for every 106 incident photons.Assume that the sphere is isolated are instantly swept away after emission
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5 Answers
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if N0 is total no of photons emitted...
then photons incident on sphere will be..
N0(1-cosθ)
2
now try...
3yes sry da mistaken with the radius of the sphere
then i can do da
tx for ur reply
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33well....
In AITS... the questions are small ones... with just strike and tick type...
But it is no less than them, far better i'll say...