1ya i hav d solution bt m nt egttin it i mean hw can one get uas x and itz image at x+y ?
can u plez gimme a diagrm for d same or sum eg
an objct and a screen r mounted on an optical bench and a convergin lens is placed bewtn so dat a shrp image is recicvd on d screen . d linear
mag of d image is 2.5
d lenx is nw moved 30 cm nearer the screen
and d shrp imgae is obtaned again on d screen
d focal lenght of d lens is
? xpain wat u do in each step
plezzz
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4 Answers
1I am giving you a hint dear.
If you see carefully the lens/mirror formula ( only for real images )
The distance between the image & the object doesnot change if you swap the u & v.
I mean if an object was at a distance x left of convex lens & image was formed y distance on right side of convex lens, then distance between object & image is x+y.
Now, switch u & v.... i mean if you now place the object at a distance y left of lens then image will form x distance right of the lens. so the distance between object & image is still the same ... x+y
Its the same case here ... did u get it ??
1Ashish is right.
In the picture you can see that the distance OI is constant.
Now you got the hint ?