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a 5D lens forms a virtual image wich is 4 tyms d object placed perpendicular on d principal axis of d lenx find d distnce of d objct frm d lens

2 Answers

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1/f = 5
as image formed is virtual ... so image is formed on the same side of lens.
also v=4u

1/v - 1/u =1/f
=> 1/4u - 1/u = 5
=> u = - 3/20 ( negative value means that its on left side of lens )

1
°ღ•๓яυΠ·

ya meko bhii same aaya tha woh meri aabhi chamki ki 3/20 =15cm ....dozzzzzzzzzzin

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