1/f = 5
as image formed is virtual ... so image is formed on the same side of lens.
also v=4u
1/v - 1/u =1/f
=> 1/4u - 1/u = 5
=> u = - 3/20 ( negative value means that its on left side of lens )
a 5D lens forms a virtual image wich is 4 tyms d object placed perpendicular on d principal axis of d lenx find d distnce of d objct frm d lens
1/f = 5
as image formed is virtual ... so image is formed on the same side of lens.
also v=4u
1/v - 1/u =1/f
=> 1/4u - 1/u = 5
=> u = - 3/20 ( negative value means that its on left side of lens )
ya meko bhii same aaya tha woh meri aabhi chamki ki 3/20 =15cm ....dozzzzzzzzzzin