33
Abhishek Priyam
·2009-02-04 10:37:04
lol ...
in my mind i assumed that it is increased.. but is it r8..
pata nahi-> i don't know
1
voldy
·2009-02-05 04:50:51
n = A + B/λ2 .
so put this in the eqn for the R.I
n = sin (A+D / 2) / sin(a/2)
now . well cross multiplying , we get some constant.+ nB/λ2 = sin ( A+D)/2 .
then we know that . v=fλ . so we get . that as we increase f , the D increases no ? I don't know whether this's right.
33
Abhishek Priyam
·2009-02-04 10:43:35
ncreasing the frequency will decrease the refractive index of t....
it should be opposite..
1
?
·2009-02-04 10:43:27
λ=c/ν ...RITE SANKARA ?
then μ proprtional to v
1
?
·2009-02-04 10:41:21
naa ..rey angle of minimum deviation increases if u increase the frequency
1
MATRIX
·2009-02-04 10:40:22
loooo aagaya sankara[4][4][4]
1
MATRIX
·2009-02-04 10:38:26
oh then type pataaa nahii!!!!ok abhishek!!!!!!![4][4][4][4]
3
msp
·2009-02-04 10:38:05
i know a relation
μ=k+B/λ2 k,B are +ive constants.i think this relation is know as cauchys formula
λ=c/ν
increasing the frequency will decrease the refractive index of the prism and therefore it decreases the minimum deviation angle
1
MATRIX
·2009-02-04 10:25:40
it will increase Abhishek am i rite?!!!!!!!![4][4][4][4]
1
?
·2009-02-04 10:34:09
ok but u didnt specify whether the u are increasing or decreasing the frequency
1
?
·2009-02-04 10:32:28
A.D = d@/dA
here @ = angle of minimum deviation
and A.D inversely proportional to the cube of the wavelength
33
Abhishek Priyam
·2009-02-04 10:31:54
dimag mera kharab hai aaj [2]
33
Abhishek Priyam
·2009-02-04 10:31:13
i think got it..
λ decreases so μ increases.. hence angle of min dev.. increases
1
?
·2009-02-04 10:29:38
angular dispersion will change ...now as it is related to angle of minimum deviation , it will also be affectd