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What will happen to angle of min deviation in case of prism if we change frequency of light..
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lol ...
in my mind i assumed that it is increased.. but is it r8..
pata nahi-> i don't know
n = A + B/λ2 .
so put this in the eqn for the R.I
n = sin (A+D / 2) / sin(a/2)
now . well cross multiplying , we get some constant.+ nB/λ2 = sin ( A+D)/2 .
then we know that . v=fλ . so we get . that as we increase f , the D increases no ? I don't know whether this's right.
ncreasing the frequency will decrease the refractive index of t....
it should be opposite..
i know a relation
μ=k+B/λ2 k,B are +ive constants.i think this relation is know as cauchys formula
λ=c/ν
increasing the frequency will decrease the refractive index of the prism and therefore it decreases the minimum deviation angle
ok but u didnt specify whether the u are increasing or decreasing the frequency
A.D = d@/dA
here @ = angle of minimum deviation
and A.D inversely proportional to the cube of the wavelength
i think got it..
λ decreases so μ increases.. hence angle of min dev.. increases
angular dispersion will change ...now as it is related to angle of minimum deviation , it will also be affectd