Q4. Ph-OH + CH3I ?
Ques 4) Find the product formed in this reaction:-
C6H5 - O - CH3 + HI ---(heat)→ ???
Ques 5)
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8 Answers
qwerty
·2009-12-20 20:18:49
Q4]
products: C6H5I + CH3I + H2O
Note: reactions of ethers withcold HI and hot HI is diff,
products above are for hot HI, for cold HI, u get alcohol + haloalkane
Avinav Prakash
·2009-12-21 03:16:04
can any1 plz tell me why(CONCEPT) for cold HI , PhOH and CH3I R Formed ????
Pritish Chakraborty
·2009-12-21 03:22:17
Another piece of info : This reaction is SPONTANEOUS because a gas(SO2) is being evolved, so the carbocation formation WILL occur in absence of pyridine. This wouldn't work had it been an aryl/vinyl group holding D and OH.