Alcohols Doubts 4,5

Ques 4) Find the product formed in this reaction:-
C6H5 - O - CH3 + HI ---(heat)→ ???

Ques 5)

8 Answers

106
Asish Mahapatra ·

Q4. Ph-OH + CH3I ?

19
Debotosh.. ·

in qs 2 ,,is pyridine present or absent ?

11
swaraj jena ·

q 5>possible products

is it correct

11
swaraj jena ·

Q4> is the answer C6H5I

23
qwerty ·

Q4]

products: C6H5I + CH3I + H2O

Note: reactions of ethers withcold HI and hot HI is diff,
products above are for hot HI, for cold HI, u get alcohol + haloalkane

1
Avinav Prakash ·

can any1 plz tell me why(CONCEPT) for cold HI , PhOH and CH3I R Formed ????

39
Pritish Chakraborty ·


Another piece of info : This reaction is SPONTANEOUS because a gas(SO2) is being evolved, so the carbocation formation WILL occur in absence of pyridine. This wouldn't work had it been an aryl/vinyl group holding D and OH.

11
Tush Watts ·

yup correct Pritish

Thanx [1]

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