106(a) ?
Ques) Among the following, the compound which does not forms a white precipitate on treatment with NaI in acetone is :-
(a) CH3 CH2 I (b) CH3 CH2 C l (c) Ph CH2 C l (d) CH2 = CH - CH2 C l
C l dentoes chlorine
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9 Answers
106There's ethyl iodide,, so if it reacts with NaI it wont form anything. sincewe already have I there
13Doubt frm my side--- In this Halide Exchange rxn, how come I- being a weaker Nucleophile than Cl- , is able to replace it ??
1yeah you can say it's halide exchange method. And precipitate will only occur when a group other than AgI is formed like AgCl or AgBr, these are the only ppts (you must have done practicals, AgCl ppt is not soluble in AgNO3, AgBr is partially soluble while AgI is completely soluble).
Hope this clears!
11@ AVIK
The feasibility of this reacn is due to solubility of Na I in acetone and more nucleophilic character of I- ion . The reaction proceeds by SN 2 mechanism and is possible bcoz Na Cl and Na Br are precipitated in this reaction , as they are not soluble in weakly polar aprotic solvent.