Organic Chemistry - another one

62

Lokesh Verma ·2009-02-15 04:13:16

It depends on the no of moles of the reactant.

If I assume that the added Ozone and NaOCl are in access..

then

M will be CH₃COCH₂CH₂COCH₃

if NaOCl is in excess
then N should be
NaOOCH₂CH₂COONa

CCl₃COCH₂CH₂COCCl₃ will be the intermediate.

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62

Lokesh Verma ·2009-02-15 04:56:20

iodoform reaction?

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62

Lokesh Verma ·2009-02-17 23:03:43

subash what is the correct answer?

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prateek punj ·2009-02-17 23:31:33

yes nishant bhaiya i agree with ur ans...
the first one is reductive ozonolysis and the second one is iodoform in which the methyl keto will convert its iodoform....

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mkagenius ·2009-02-17 23:36:08

i agree wth ur answer,sir.

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11

Subash ·2009-02-19 06:50:55

bhaiyya ur second one is wrong i think

n really sorry for the late reply :)

can u give the mech of the second one

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big looser ......... ·2009-02-19 06:54:47

wat is this second reaction

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62

Lokesh Verma ·2009-02-19 06:59:02

subash you are right.. but for the reaction you are doing .. if there was a constrain to the amount of NaOCl then only one side would have undergone iodoform

what do you think?

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11

Subash ·2009-02-19 09:31:37

yeah bhaiyya i agree with you the amounts should have been mentioned

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voldy ·2009-02-19 17:47:39

no nishant is right . only on aicdification do we get the product given by Subhash

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