Swaraj..(CH3)2CMgBr..something is missing here..i mean the valency of cabon shud be 4..which is not here..plz edit it..
and the first compound is a ketone so the alkyl part of Grignard reagent will be attached to ketonic carbon..and OMgBr is formed..then if u add water then tertairy alcohol will be formed...
(CH3)2CHCOCH(CH3)2+(CH3)2CHMgBr (G.R) WILL PRODUCE????????? ANSWER EXPLAINING MECHANISM
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9 Answers
govind
·2010-02-26 04:00:07
katoch
·2010-02-26 07:53:00
the answer to ur question is
[(CH3)2 CH]3-C-OMgBr
without hydrolysis. after hydrolysis it will form [(CH3)2 CH]3-C-OH.
IN G.R. BOND BETW. R-Mg IS POLAR SO R DEVELOPS A PARTIAL -VE CHARGE AND Mg DEVELOPS A PARTIAL +VE CHARGE.
SO THE R GROUP ATTACKS THE CARBONYL CARBON.
Asish Mahapatra
·2010-02-26 21:30:09
dont you guys think that steric hindrance is a bit too high here??
Pritish Chakraborty
·2010-02-27 03:47:15
http://www.organic-chemistry.org/namedreactions/grignard-reaction.shtm
As per this, the starting ketone itself is the end product because it is sterically hindered.