1@PRITISH
ITNA SAANATA KYUN HAI BHAI.........BATA NA PLZ.................
19 Answers
1
39It's given in Wiki also...normal method of preparing allyl magnesium halide. Dunno why it's given false, it should be true.
1YAAR I TOO THINK SO BUT IT WAS GIVEN AS TRUE N FALSE QUESTION N ANSWER WAS GIVEN FALSE.........
1***********NAGADAROLLLLLLLLLLLLLL***********
WAT I TOLD BOUT SECOND ONE U WILL BE GASPING READING ANSWER LOLLLLLLLLLLLL[1][1]
1yaar allyl bromide on treating with Mg in dry ether gives what?????????
[m not joking asking this m serious[1]]
39BECAAAAAAAUSE
*drumroll*
Secondary carbon :P..I was having doubts about the solvent as well. Acetone jo hai...if SN2 is forced well enough by acetone koi problem nahi hai :) the answer given by your source is right.
But the second?
1is it EtSSO3 or EtSCO3 ???
@pritish
and why SN1 in case 1 ??? I see 2° n acetone SN2 is very much possible
the the product will be the one given.
39I-PrBr is isopropyl bromide or...?
The nucleophile is ambident...check out my notes (HASB Theory part) :)
39LOL have they given any explanation?
First product mein nitrogen should be the connecting atom..not sulphur, am damn sure.
Second product toh I couldn't have thought of even in my dreams!
39Isopropyl bromide mein SN1 hoga...and carbocation is hard acid. Nitrogen is the harder base. So we will have isopropyl isothiocyanate as the product.
Ethyl bromide will undergo SN2. Partially charged carbon is soft acid. Sulphur is the softer base in this case. So here it will be ethyl thiocyanate.
1arey yar hard-soft padh rakha hai par tu sirf final product bata plz.........