dbt...only give ans..

10 Answers

39
Pritish Chakraborty ·

I > III > II?

24
eureka123 ·

ya.. how??

39
Pritish Chakraborty ·

Cyclopropane rings are highly strained because their bonds are packed at 60 degree angles. If they are attached to electron withdrawing groups, or if they gain a positive charge, they will gain a little stability. Thus the order of preference.
Carbocation is the most electron deficient, followed by radical followed by carbanion.

24
eureka123 ·

i thought we had to do this on aromatic stablity instead ......since it was attached to a aromatic passage...

39
Pritish Chakraborty ·

Well thats how my friend explained it to me...I find this explanation easier lol
But yes, it should be done on basis of aromaticity, because a double bond is there...woh toh dekha hi nahi maine!

29
govind ·

The reason comes from aromaticity in this case..
ok now what abt this ...arrange them in the increasing order of stability,..
Ph3C+ , tropylium , compound 1 given in abv question...
the attached image is of tropylium

1
Tapas Gandhi ·

triphenyl carbocation(9)>tropylium(7)> comp 1 above(3) resonating structures

1
Avinav Prakash ·

tropolium > comp 1> triphenyl carbocation

tropylium...it doesnot lose aromaticity..

29
govind ·

compound 1 > tropylium > Ph3C+
1014 1011 1 relative order of stability

Source : Peter Sykes

24
eureka123 ·

thx everyone [1]

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