19CH3Cl>CH2Cl2 >CHCl3 >CCl4
here the trick lies in asserting that CHCl3has lesser dipole moment than CH3Cl !!!
arrange d molecules in decreasing order of dipole moment.
CH3Cl, CH2Cl2, CHCl3, CCl4
plz explain the solution.
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4 Answers
191can u plz explain the ans it will be very helpful for the aspirants here
especially for the second and third term
19let me compare between CH3Cl(1) and CHCl3(2)
the dipole moments in both 1 and 2 are additive(that can be shown by drawing the tetrahedral structures of the two compounds and then finding the directions of bond polarity for each bond). Cl tends to have a ∂- charge due its strong electro negativity and hence in 2 the Cl-Cl repulsion occurs as a result of which the Cl-C-Cl bond angle increases. we know that vector addition involves cos{bond angle}...hence as the bond angle increases the cosine value decreases and as a result the resultant dipole moment decreases !
1is it the real reason for which Cl-C-Cl bond angle increases again i am wondering or its that u being so dumb to analyze the facts correctly
