In this year JEE R-S and E-Z nomenclature is excluded, so don't study that [3]
1)Is there any case where a carbocation re-arranges through 1,2 -CH3 migration even when there is an alpha hydrogen present (to carbocation)?
2)How do we name cyclohexene as E/Z configuration? It is symmetric on both sides of the double bond....
3)In case of aromatic compounds, how do we find out whether an atom is chiral (some compounds are symmetric w.r.t a given atom i.e. they form a ring)?
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12 Answers
1) The migratory aptitude of the hydride ion is the greatest. Hence unless there is any hindrance to it, hydride and not methyl shift will occur.
I think it won't be good to neglect RS and EZ Nomenclature.
How to solve problems without them then?
For question two:
Bicyclic (Not Bridged Bicyclic) comounds are always in Cis form. So it should be Z I presume!?
How do we name cyclohexene as E/Z configuration? It is symmetric on both sides of the double bond....
I donno if I am right but one thing that I can think about is that we can draw chair form of cyclohexene and then see the atoms attached to the carbon at the equitorial position and axial position w.r.t the double bond.
3)In case of aromatic compounds, how do we find out whether an atom is chiral (some compounds are symmetric w.r.t a given atom i.e. they form a ring)?
if compounds are symmetric with respect to certain atom then that atom is of course achiral.
For the atom to be chiral it should have all different groups attached to it, is shouldn't possess any symmetry.
@ Pritish,
Vivek kuchh jyada hi padhne laga hai, lagta hai[3], may be cyclohexene is a bicyclic compound is his new discovery [3]
I donno if I am right but one thing that I can think about is that we can draw chair form of cyclohexene and then see the atoms attached to the carbon at the equitorial position and axial position w.r.t the double bond.
It will be still symmetrical I think.
OOps..
It'll be cyclic. (Since I've already mentioned something in brackets)
And Cis- Only.