106moles of ethane required = (55*2/58)*(100/85)*100/90
vol of ethane at ntp = no.of moles * 22.4 (litres)...
must be verry wrong....
n-butane is produced by the monobromination of ethane followed by wurtz rxn, calculate the volume of ethane in litres at ntp to produce 55 gm of n butane if bromination takes place with 90%yield and the wurtz rxn with 85%yield ....
asked by aarthi.
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3 Answers
106106see. in wurtz reaction .. one mol of butane is formed from 2 noles of ethane bromide ..
now. 55 gm butane i.e. 55/58 moles of butane are formed .. so no of moles of ethane bromide rqd = 2*55/58
now .. efficiency of wurtz is 85% . so actual moles of ethane bromide reqd is (100/85)*(2*55/58)
efficiency of bromination is 90% hence acual moles of ethane reqd is (100/90)*[(100/85)*(2*55/58)] = a (say)
so. moles of ethane reqd at ntp = 22.4*a litres
