Easy one in organic..

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n-butane is produced by the monobromination of ethane followed by wurtz rxn, calculate the volume of ethane in litres at ntp to produce 55 gm of n butane if bromination takes place with 90%yield and the wurtz rxn with 85%yield ....

asked by aarthi.

#Chemistry #Organic Chemistry

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106

Asish Mahapatra ·2009-03-15 21:46:56

moles of ethane required = (55*2/58)*(100/85)*100/90

vol of ethane at ntp = no.of moles * 22.4 (litres)...

must be verry wrong....

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106

Asish Mahapatra ·2009-03-15 23:15:50

see. in wurtz reaction .. one mol of butane is formed from 2 noles of ethane bromide ..

now. 55 gm butane i.e. 55/58 moles of butane are formed .. so no of moles of ethane bromide rqd = 2*55/58

now .. efficiency of wurtz is 85% . so actual moles of ethane bromide reqd is (100/85)*(2*55/58)

efficiency of bromination is 90% hence acual moles of ethane reqd is (100/90)*[(100/85)*(2*55/58)] = a (say)

so. moles of ethane reqd at ntp = 22.4*a litres

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AARTHI ·2009-03-15 23:17:42

tx..bhaiyya tx ashish

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Easy one in organic..

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