19no answers expected???? confirm ??? i will answer myself !!
1the -OH, -NH2, donate lp so the H are not so acidic
19
Debotosh..
·2009-08-21 21:01:59
@rickde.....please elaborate !!!!
19
Debotosh..
·2009-08-22 09:43:37
Due to the development of acetate ion the fourth OH- attack the system thereby inhibiting the reaction !!!(i hope you know that haloform involves use of 4 OH- ions)
11l.p. reduces positive charge on c-atom.....
1
rickde
·2009-08-31 05:43:52
l.p reduces positive charge on the carbonyl carbon. now the +ve charge is responsible for making the H in CH3 acidic by stabilising the carbanion formed after removal of the H
as the + charge intensity decreases the carbanion becomes less stable making the H less acidic
thus the removal of H becomes more harder making the haloform reaction less feasible
also the removal of H is the rate determining step
