1
utd4ever
·2010-04-06 00:00:53
is the answer (CH3)2-CCl-CH2-CH3 ....
29
govind
·2010-04-06 00:04:43
here in this compound we have
1 tertiary H
2 Secondary H
9 primary H
since the ratio of attack is tertiary : secondary : primary = 5 : 3.8 : 1
so the final ratio becomes
1 tertiary H = 5
2 Secondary H = 7.6
9 primary H = 9
so attack on primary carbon will yield the major product..and for the percentage u can do 9/21.6 * 100 = 41 %
1
utd4ever
·2010-04-06 00:08:54
since it is i the presence of light it should be free radical mechanism .. so most stalbe free radical will be formed that is tertiary so we will get the answer i gave ..... wondering why thats not the answer ???!!!!
39
Pritish Chakraborty
·2010-04-06 00:13:56
utd4ever look up Reactivity-Selectivity principle..
1
utd4ever
·2010-04-06 00:14:01
ur explanation is correct but lubu told me that the answer is secondary carbon ??