1ok
calcium carcbide + water = ehtyne
C2H2 -1 mol H2 ,Pd - >C2H4
treat C2H4 with HCN and u will get the result
15 Answers
1
1truly ?
isn't HCN a weak acid. not very satisfying yield. might be a good theoretical method.
but in organic chemistry never deals in only theoretical part .practical part is far more important.
1CaC2 + 1)h20 , 2) lialh4/ h+ (converting to ethene), 3) HBr, 4) HCN -> CH3CH2CN
1 step !!! ( :P ;) )
1@sky
i think for better yield your fourth step should be with NaCN
1LiAlH4 ? to convert into ethene. any better method?
and at ITT goer . u r right.
one of the age old methods still practised in some primitive places if I'm right? else forgivre me.
1At rohan u r right in the 4 th step.
any body another method in 3 steps?
1hahahaaa . nice try . the you add all the rectants in one go? then in the third reaction and fourht reaction . NaCN and HBr will react to give HCN ad NaBr
How's that.?
and actually what u've givne is a five step process
1atleast I thinkso . if worng correct me . I mean the reaction b/w NaCN and HBr
1hehe :)
i dun thnk NaCN will form HCN... HCN a weak acid... CN- strongr base...
btw, leave it :P
1truly?
there exists CN- in the mdm right? the salt NaCN is perfectly ionic . no doubt there right? then there is HBr a strong acid. thus there is H+ in the mdm . CN- and H + in the mdm , won't they combine? U have only said that CN- is a storng base.??
1ok , then give a better substitute for your LiAlH4 , then your method seems alright , yet not in 4 steps , the thing is u've tried. well done think of other methods.
Now, find a replacement for LiAlH4.
and add the reagent only one rection is complete no? pleasee.
19i just cannot gauge the exact stupidity of the entire discussion : you guys and gals are producing nitrile compound by using an ionic compound like sodium cyanide (and someone using HCN) ? i donot think you know that in ionic compounds the bonding occurs from the side of carbon due to homolytic fission whereas in covalent compounds like silver cyanide the bonding occurs from the side of nitrogen (i.e. the more electronegative end)~ appropriate for nitrile formation !!!!