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why 3,3dimethylbutan2one does not give iodoform test?
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bas ravi tune kar diya mazak faaltu main.......
joke mat maar jawab de........
the compound is very stable there fore it doesn't give the iodoform test
I didn't said U r wrong.
I just wanted to show that there is enolate ion formation in the mechanism....
For the question u gave i'm not much convinced by the fact that due to enol formation poses a problem for reaction cause enolate ion are always in equilibrium with keto group and their concentration is larger in solution only when there is β diketones or any carbonyl compound in which there is resonance stabilisation or intramolecular H-bonding.
So I also think the main factor should be Stearic hindrance.....
There is a transition of Carbonyl group and the enolate ion at every stage....
So the red boxes compounds in the diagram are always in equilibrium with enolate ion.
So u can't deny the fact that there is enolate ion in the reaction.
when enol intermediate form it favours in more substituted alkene & steric effect
I agree with rahul and there is enol formation during Iodoform reaction.
If u require i can post the whole mechanism.......
even i think so rahul u confirm d thing there is no enol formation
however i support u in stearic crowding reason
tell me if i m wroong
why ?????????????????????????? rahul i didn't get your point