Now here are some questions worthdoing,Swarna do try it.....

(2) ln k = -Ea / (RT) + ln A where k is the rate constant, Ea is activation energy, R is the universal gas constant and A is some constant specific to a reaction
A more useful way to write this is in this case is:
k = Ae^ (-Ea / (RT) (Arrehenius equation)
k₁k₂ = (A.e^ (-Ea₁ / (RT)) (A.e^ (-Ea₂ / (RT))
The A cancels out.
Ea₁ = (37012 - 2% of 37012)calorie
Ea₂ = 37012 calorie
R=1.985 cal K^-1 mol^-1
T=300 K
u can calculate it .......
here we are getting the ratio of k₁ and k₂
u can also calculate k₂and k₁ individually as percentage of product molecules are given....

volume of first beaker 17 ml
volume of second beaker 23 ml (approx)