Option

either answer all these ques..or tell me an online source from where I can learn about these all isocyanide reactions .............

1) ethyl isocyanide on reaction with Na/alcohol = ??
2) acetaldoxime reacts with phosphoruous pentoxide to give ??
3) acid hydrolsis of methyl isocyanide gives ??
4) methyl isocyanide reacts with chlorine to give ??

21 Answers

1
aieeee ·

1) i'm not very sure but this rkn should take place in the presence of a reagent furnishing H-. the given reagent only supplies H+.

1
aieeee ·

if more moles are used then, activity of Cl- will be more as ders possibilty of +ve charge on C , and also H+ also needn't be extracted out due to hindrance by two Cl groups.

also N- can't sustain another electronegative atom like Cl. thus, Cl+ would remain unreactive.

24
eureka123 ·

i hope it will same

1
aieeee ·

k. posting.just a minute.

24
eureka123 ·

so how will be mech in 4 then using 1 mol of Cl ??

1
aieeee ·

welcome.[1]

24
eureka123 ·

hmmm.........let me think on it then..,,

anyways thanxxxxxx[1][1]

1
aieeee ·

frm reagents like LiAlH4 or NaBH4 or NaH etc. anyone of reagents furnishing H- should hv been mentioned.
i strongly think so. but, if mechanism could be approached in any other way , then ?????

24
eureka123 ·

but from where will H- come ??

1
aieeee ·

4) ya, right. i hv taken two moles of Cl2 , dats why its coming so. otherwise the answer u hv given is right ( with a single mole of Cl2 ).

1) and 1st reaction should take place in the presence of H- , otherwise when H+ is added to C- in the substrate , the reaction proceeds in the backward direction and again the substrate is formed ( in the absence of H- )

24
eureka123 ·

Ans4 a bit wrong...here is the answer....

and one dbt in soln1 ......from where is that H- coming???

1
RAY ·

3. ch3cooh......

1
aieeee ·

4) this reaction takes place in aqueous solution.

1
aieeee ·

3)

1
aieeee ·

help hs come.

2) NOTE : keto form is more stable thn enol form. so tauto merism takes place.

24
eureka123 ·

plz help me guys.....

24
eureka123 ·

hmm really ???
can u give the names ??
so that i can find easily ?

24
eureka123 ·

i want mechanisms....i have the answers

4
UTTARA ·

2 ) CH3-N≡ C ----(acidic hydrolysis)----> CH3-NH2 + HCOOH (Formic acid).....this is also a test 2 distinguish b/w cyanides & isocyanides ...

4
UTTARA ·

4 )CH3-N≡C + X2 ------> CH3-N=CX2 .... (X is a halogen).....

4
UTTARA ·

1 ) R-N ≡ C + Na/alcohol -------> R-NH-CH3 ..... Na/alcohol is a reducing agent....

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