1) i'm not very sure but this rkn should take place in the presence of a reagent furnishing H-. the given reagent only supplies H+.
either answer all these ques..or tell me an online source from where I can learn about these all isocyanide reactions .............
1) ethyl isocyanide on reaction with Na/alcohol = ??
2) acetaldoxime reacts with phosphoruous pentoxide to give ??
3) acid hydrolsis of methyl isocyanide gives ??
4) methyl isocyanide reacts with chlorine to give ??
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if more moles are used then, activity of Cl- will be more as ders possibilty of +ve charge on C , and also H+ also needn't be extracted out due to hindrance by two Cl groups.
also N- can't sustain another electronegative atom like Cl. thus, Cl+ would remain unreactive.
frm reagents like LiAlH4 or NaBH4 or NaH etc. anyone of reagents furnishing H- should hv been mentioned.
i strongly think so. but, if mechanism could be approached in any other way , then ?????
4) ya, right. i hv taken two moles of Cl2 , dats why its coming so. otherwise the answer u hv given is right ( with a single mole of Cl2 ).
1) and 1st reaction should take place in the presence of H- , otherwise when H+ is added to C- in the substrate , the reaction proceeds in the backward direction and again the substrate is formed ( in the absence of H- )
Ans4 a bit wrong...here is the answer....
and one dbt in soln1 ......from where is that H- coming???
help hs come.
2) NOTE : keto form is more stable thn enol form. so tauto merism takes place.
2 ) CH3-N≡ C ----(acidic hydrolysis)----> CH3-NH2 + HCOOH (Formic acid).....this is also a test 2 distinguish b/w cyanides & isocyanides ...
1 ) R-N ≡ C + Na/alcohol -------> R-NH-CH3 ..... Na/alcohol is a reducing agent....