In 4th one there should be another bromine atom on the other carbon of the double bond, and zinc will abstract both to form a triple bond.
In 3rd,
Pehle waale ka ans toh tune hi de diya..
In 4th one there should be another bromine atom on the other carbon of the double bond, and zinc will abstract both to form a triple bond.
In 3rd,
Pehle waale ka ans toh tune hi de diya..
listen in 1 iwant to ask whethet it will reduce both the double bond or one as mole of H2 is not specified
and in 2 whether redP and HI will reduce all the functional groups .then what is the answer
in 4 one as the reduction of alkyl hallides takes place for saturated hallides.how this will occur