ORGANIC REACTIONS4

27 Answers

1
JOHNCENA IS BACK ·

ok..u only tell correct answer.......my ans. is one i posted in #11

1
voldy ·

well dude . see the -I of NO2 can be neglected .

the +I effect of C ofcourse has to b taken nito account

here the stabilising factor comes from resonace with NO2 grp

try writing the resonance structures is my advice u should get it

1
JOHNCENA IS BACK ·

nope............u din get what i meant in 2nd reason........

i said NO2 HAS -I ON RING........RIGHT.ALSO,CH2 HAS +I EFFECT ON RING...............RIGHT!!!!!!!!!!SO, CLEARLY 2ND RADICAL WOULD BE VERY UNSTABLE...........HMMMMMMMM.

IN FIRST RADICAL TOO NO2 HAS -I ON RING.........BUT THIS TIME CH3 ON OTHER SIDE OF CARBON HAVING FREE ELECTRON WUD STABILIZE FREE RADICAL DUE TO +I EFFECT....................

DID U GET WAT I MEANT IN 2ND REASON.......

PLZ REPLY!!!!!!!

1
voldy ·

u said that the inductive effect dies with 4 carbons na ????

to now -I kahaan se aagaya ? for NO2 ???[7] the first one seems ok for me

1
JOHNCENA IS BACK ·

srinath

r reasons i gave in#23 wrong

1
voldy ·

no dear I'm sure :)

try writing resonance structures . u should be able to get it ya I'll post later

1
JOHNCENA IS BACK ·

@ROHIT U R WRONG.................................................
SRINATH DA I CORRECT........

2 REASONS FOR THAT U SELECTED WRONG FREE RADICAL AS MORE STABLE........

1)STABILITY OF FREE RADICAL INCREASES AS PRIMARY<SECONDARY<TERTIARY!!!!!!!!!!!!!![3]

2)NO2 IS -I GROUP AND CH2 IS +I GROUP......SO SECOND FREE RADICAL U DREW WUD NOT BE STABILIZED(COMPARED TO FIRST ONE).....COZ IN FIRST ONE -I EFFECT OF NO2 WUD BE NULLIFIED(TO SOME EXTENT) DUE TO +I EFFECT OF CH3......MAKING FIRST FREE RADICAL MORE STABLE...........................................................

............SRINATH DA PLZ REPLY TO THIS ONE!!!!!!!!!!!!!

1
RAY ·

n can u clarify to me??how ill free radicals b stabilised by --R groups??i dun find any logic behhind it?????

1
RAY ·

here if u name d above radical as 1...n d below one as 2...den in 1...wen there will b resonance due to ....--N+=0.....den der will b ∂+ charge at the ortho n para position...so dey will attract away electron from d free radicalln not donate electron to it...so d free radical 2 is much more stable......

1
RAY ·

see guys i understand dat the answer is becoause u wanna say by +I effect d free radical will b stabilised..

but srinath u r wrong brother..free radical r only stabilised by +i..or resonance..as dey have shortage of electron...so if d radical u guys r saying is forming..it will b de stablised by d del + forming on d carbon near it...due to d no2...hope u get it....

1
JOHNCENA IS BACK ·

no.....no.nothing like that........you are like my big bro.........just assuring u!!!!!!!!

1
voldy ·

hey dude don't get me wrong or anythign . I was only stressing that you learn the cnocept that's all nothing more

. free radicals are stabilised both by +R and -R groups

will try to post more problems now don't have much time will certainly do so when I find some. :)

1
JOHNCENA IS BACK ·

before.........actually i saw ur reply to relative reactivity thread.........n came here to ensur e whether i posted correct image or not!!!!!i saw u had not posted any comment till then n i posted wrong image.so instantly changed the image...just when the message of successful post appeared ....i saw ur point that ans. is wrong......................[1]...........don worry i won't ever cheat u or anyone else.........u can trust me that much[1]

1
voldy ·

wel well . that's right :)

when did u edit it ??when i told it was wrong or before ??[/hide

1
JOHNCENA IS BACK ·

koi to batao!!!!

1
voldy ·

no the asnwer given by rohit and you is wrong

1
RAY ·

i added cl ...add br der....

c in second case...no2will have del + charge at para..so del + will attaract away e ...so make it unstable...

1
RAY ·

here if u name d above radical as 1...n d below one as 2...den in 1...wen there will b resonance due to ....--N+=0.....den der will b ∂+ charge at the ortho n para position...so dey will attract away electron from d free radicalln not donate electron to it...so d free radical 2 is much more stable......

1
JOHNCENA IS BACK ·

1
JOHNCENA IS BACK ·

OKAY........ONE MORE TIME.....LOOSE.......LOOSE CONTROL(RANG DE BASANTI)[1]

1
voldy ·

try dude . organic is fun . try it . only then will u remember longer. else if i give the asnwer u'll forget it quickly . generally this is what happens .

one clue

FR process

1
JOHNCENA IS BACK ·

HEY SRINATH PLZ POST YOUR ANSWER!!!!!!!!!(+REASON)

1
JOHNCENA IS BACK ·

i don think it is right........but just thought so.............plz u only post the answer and explanation!!!!!!!!!!!

1
voldy ·

why do you think this answer is right ???[7]

b/w ans is wrong !![3]

1
JOHNCENA IS BACK ·

1
JOHNCENA IS BACK ·

ok.posting my answer

1
voldy ·

what do u think is the answer??

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