ORGANIC!!

1) CC --- C C + 1EQ. HCl at liow temp. GIVES ???

2) CC --- C ---- C C + 1EQ. HCl at liow temp. GIVES ???

34 Answers

1
Optimus Prime ·

answer for 2nd is C-C-(Cl)-C-C≡C

1
gsns gannavarapu ·

kk thx i understud

1
greatvishal swami ·

tapan it was to prov that double bonds reacts faster than triple as unstable vinyl cation is formed
( that i showed in the fig)

but also in Q 1 H+ still attacks triple bond such that overall stability is not disturbed

first the compound was stable due to conjugation hence for the product to remain in conjugation H+ attacks triple bond

always consider overall stability of compound first

1
gsns gannavarapu ·

sry if i m irritatin u i gt another doubt
can d 2nd compound b

C - C(Cl) - C - C ≡ C

1
greatvishal swami ·

yeah ur rite

21
tapanmast Vora ·

Vish : My dbt in Q1 is not werther duble or tripl bond is attacked........ that's triple 4 sure

Ther two Carbons mutually triply bonded......... extreme rite wala n the one next to it.....

Now Cl will go to wich C out of the two is ma DOUBT,.......

1
king_khan ·

hey dat is bcoz of greater stability of the carbocation !!!

1
greatvishal swami ·

hmm now i got u k k

next to it will be attacked as that carbocation is more stable due to conjugation with double bond

1
Optimus Prime ·

answer for 1st is C=C-C(Cl)=C

21
tapanmast Vora ·

Vish how does the abov diag. justify prodct 1?? [7]

in Q1 the terminal triply bonded C

1
vector ·

vishal cud u plz explain things a bit more clearly

1
greatvishal swami ·

[4][4] k k

wait a min

1
greatvishal swami ·

after addition of H+

CC-----C+c----H ( charge is conjugated)

and

CC-----Cc+----H ( charge is not conjugated)

r possible

clearly 1st carbocation is more stable than 2nd due to conjugation with double

bond hence Cl- will bond with 1st structure

1
vector ·

thanks wud u also explain 2nd one

1
greatvishal swami ·

richa 2nd one is easy simply on the facts that

1. double bonds are more reactive than triple

2. 20 carbocation is more stable than 10 carbocation

1
vector ·

bt wat s the significance of low temp

1
greatvishal swami ·

low temp hmm its exothermic reaction naa ( and i think highly isothermic maybee)

so low temp will provide slow rate of formation ( or kindof correct rate if its highly exothermic)

something like this [4][4]

1
greatvishal swami ·

nahi double bond is attacked

21
tapanmast Vora ·

ANS :

1) C=C-C-(Cl)=C

2) C-C-(Cl)-C-C [TRIPLE BOND] C

I wanted to know the reasoning.......... I cudnt figure out one!! [2]

106
Asish Mahapatra ·

@tapan a possible explanation for 1:
a stable alkene forms as it becomes conjugated... but i dont think that applies for 2nd one then :(

13
deepanshu001 agarwal ·

nd wat happens at high temp....

1
greatvishal swami ·

at high both thebonds are attacked

1
greatvishal swami ·

well use two concepts here
1. in general duble bonds r more readily attacked than triple ( this explains for 2)

2. conjugated alkene is more stable so in 1 rather triple bond is attacked so such that the conjugation is not disturbed

13
deepanshu001 agarwal ·

how can both bond b attacked wen 1 equivalent is given

1
greatvishal swami ·

k for 1 eq u r asking

k then the same products will be formed [4]

1
gsns gannavarapu ·

will 2nd 1 b

C= C - C - C(Cl) = C ??

106
Asish Mahapatra ·

i think .. double bonds are more reactive towards electrophilic addition reactions so i think with 1 eq. of HCl only the double bonds will get broken...
i.e.
1 will be Cl-C-C-C≡C

1
gsns gannavarapu ·

y can u xplain plz??

1
greatvishal swami ·

k

well in an electrophilic addition (add of H+ here)

less stable vinyl cation is formed

1
gsns gannavarapu ·

bt dis carbon z sp hybridised naaa

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