stability of a molecule is proportional to no of resonance structures.
Arrange the following in decreasing order of stability :
1. CH2=C=CH2
2. CH2=CH-CH2-CH=CH2
3. CH2=CH-CH=CH2
a. 1>2>3
b. 3>2>1
c. 3>1>2
d. 2>1>3
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7 Answers
JOHNCENA IS BACK
·2009-06-02 20:55:28
3 is a conjugated species hence most stable
in 2 not all bonds are conjugated hence lesser
and in 1 least
so,3>2>1
RAY
·2009-06-03 00:15:18
see in 2 we have 4 hypersonjugation possible alpha hydrogen...so 3>2>1...3 is ofcourse resonance stabilised....
in 1 though we have ....alpha hydrogen but hypersonjugation is not possible....as there is no electronegitivity difference...