the point is...(when 2 adjacent-OH are present)
First -OH leaves from place where stable carbocation is formed.. then from adjacent poition one group migrates so as to form C+ at carbon having -OH..
So if methyl grp migrates then the one I gave will be formed.. and if the carbon of the ring migrates thus making it 5 membered... and the one u gave will be formed.
Also there is no much differnece between 6 and 5 membered ring as there is not too much stain in 5 mem ring.
so 6 -> 5 is also possible along with 6 -> 5
I was in a hurry so missed 1 product.