I_n=\int_{-\pi}^{\pi}{\frac{\sin nx}{(1+\pi^x)\sin x}}.. n=0,1,2.....
then
A) In=In+2B) \sum_{m=1}^{10}{I_{2m+1}}=10\piC)\sum_{m=1}^{10}{I_{2m}}=0D)In=In+1
A,B,C?
yes that's right.
yup.......correct
I0 = 0I1 = ÎI2 = 0I3 = Î...So, Ans : A,B,C
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