29/10/2009

IIT JEE 2015 Coaching › Physical Chemistry questions › 29/10/2009

The Degree of dissociation of I₂ molecule of 1000^*C and under atmospheric pressure is 40% by volume.Find the total equilibrium pressure on the gas if the dissociation is reduced to 20% at the same temp.

#Chemistry #Physical Chemistry

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8 Answers

1

aieeee ·2009-10-29 19:28:35

what does degree of dissosiation of I₂ mean ?

I₂ â†’ I^- + I⁺ ?????

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1

Bicchuram Aveek ·2009-10-30 01:11:28

I think it's

I₂ â†’ 2I isn't it ? If it's then i can solve the sum

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1

D Queen ·2009-10-30 05:41:55

Aveek u r going correct..

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D Queen ·2009-10-30 10:45:41

??

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D Queen ·2009-10-31 10:00:57

Please help me

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UTTARA ·2009-10-31 21:54:17

@Aveek : I guess u're right?!!!!

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D Queen ·2009-11-01 05:07:50

Yeah but what to do next?

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1357

Manish Shankar ·2009-11-01 06:10:25

I₂(g)â†’2I(g)
P 0
P-p' 2p'
total pressure=P+p'=1
p'/P=0.4
so P=1/1.4=5/7
p'=2/7

K=(4/7)²/(3/7)=16/21

I₂(g)â†’2I(g)
P 0
0.8P 0.4P
total pressure=1.2P
K=16/21=0.16P²/0.8P=P/5
P=80/21
total pressure=1.2P=1.2*80/21=96/21=32/7=4.57 atm

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