dunno this un.....[2]
A: isothermal expansion of ideal gas against vacuum must be simultaneously adiabatic
R:the work done by system in above process is Zero.
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4 Answers
The Scorpion
·2009-03-29 11:36:07
well, in vacuum there is no external pressure acting on d system... so d system need not do any work to expand... and hence d internal energy of d system will remain constant... which implies that there's no heat exchange (or transfer) b/w system n surrounding... hence d process is adiabatic too...