Atomic Structure

AIEEE 2015 Coaching › Physical Chemistry questions › Atomic Structure

The first ionization energy of H is 21.79x10^-19J.Calculate the second ionization energy of He atom.
(According to me,
2nd I.E of He=E₂-E_âˆž
=(21.79x10^-19)x2²2²-0 (E=21.79x10^-19xz²n²)
=21.79x10^-19J given correct answer is 87.16x10^-19J...!!!! )

#Chemistry #Physical Chemistry

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2 Answers

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Rajiv Agarwal ·2012-06-12 12:10:33

You have made a fundamental mistake here. Can you figure out your mistake?

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Anik Chatterjee ·2012-06-13 02:58:11

ya...i think i should have found out the energy required to remove the 2nd electron in He⁺ in the first shell itself....isn't it?

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Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω