Plz show me how you got the answer
From 200 mg of carbon-dioxide,1021 molecules are removed.The amount of carbon-dioxide left is:
a)120 mg
b)150 mg
c)126.9 mg
d)100mg.
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3 Answers
vaibhav sharma
·2010-07-03 00:52:55
Na molecules of CO2 = 44g (Na=6.023*10^23)
10^21 molecules= 44*10^21/Na
= 7.31*10^-2
=73 mg
CO2 left = (200 - 73.1)mg = 126.9 mg