colligative properties

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a current of dry air was passed through a series of bulbs containing 1.25 g of solute A2B in 50 g of water and then through pure water .the loss in weight of the former series of bulbs was 0.98 g and in the later series 0.01 g.if the molecular weight of A2B is 80 ,calculate degree of dissociation of A2B.

#Chemistry #Physical Chemistry

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Manish Shankar ·2009-04-15 02:23:48

P^o is proportional to the loss in weight from pure water
P^o-P is proportional to the loss in weight from solution

and (P^o-P)/P^o=X_solute

now try to solve this question

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