λ = (2πr) / n
Radius of 3rd orbit = 9a , n= 3
Therefore, λ = (2π x 9a) / 3
= 6Ï€a (answer)
If the radius of the first Bohr orbit is 'a', then what is the De-broglie wavelength of the electron in the 3rd orbit?
λ = (2πr) / n
Radius of 3rd orbit = 9a , n= 3
Therefore, λ = (2π x 9a) / 3
= 6Ï€a (answer)