m =EIT/F
1000=18 X 1.5 X 106 X T /96500 X 2 X 8.2 X 1012 (dividing both sides by volume )
density of water is 1000kg/m3 so it was divided..............
Nishant sir dekhna kahin koi mistake to nahin ho gayi
lake cayuga has a volume of water estimated to be 8.2 X 1012 L.a power station not so far above cayuga waters produces electricity at the rate of 1.5 X 106 coulomb/sec at an appropiate voltage ...how long would it take to electrolyse the lake?
m =EIT/F
1000=18 X 1.5 X 106 X T /96500 X 2 X 8.2 X 1012 (dividing both sides by volume )
density of water is 1000kg/m3 so it was divided..............
Nishant sir dekhna kahin koi mistake to nahin ho gayi