eqlb

equal vol of 2 soln of pH=2 and pH=5 are mixed/Find pH of resulting soln..

13 Answers

1
Maths Musing ·

is the ans. -log[(1.001 x 10-2)/2]

1
Philip Calvert ·

new pH = -log(10-2+10-52)
??

24
eureka123 ·

no shreyan

btw what ans u get using that philip ??

1
Philip Calvert ·

mine is same as soumya's :(

106
Asish Mahapatra ·

is the solutions fully dissociating as in strong acid or is it a weak acid?

If strong acid then Philips anser is correct.

24
eureka123 ·

ans is 11.7

106
Asish Mahapatra ·

Not at all possible.. More data is missing then

It can never be basic.

1357
Manish Shankar ·

it should be 14-11.7=2.3

3
msp ·

@asish how the answer would change if the acid is strong,can u explain a bit more.

106
Asish Mahapatra ·

answer will change if acid is/are weak .. for strong wat has been done is correct i think

3
msp ·

see strong acids and weak acids were based on pH values na.

in the first soln we have [H+]=10-2 per lit

in the second soln we have [H+]=10-5 per lit

finally we have [H+]=1/2(1.001 x 10^-2)

so pH≈2.3

24
eureka123 ·

Ans given is really 11.7

anyone having dbts..check ur Yg files...Q69

3
msp ·

may be a misprint it may have asked pOH

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