equilibrium

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A reaction A + B C + D. Initially, we start with equal concentration of A and B, At equilibrium we find the moles of C is two times of A. What is the equilibrium constant of the reaction?

1/4

1/2 xplain clearly

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Rohan Ghosh ·2009-04-29 18:50:45

let the initial moles of A and B be c

at equillibrium let x moles of A (and thus the same of B) be gone

A + B => C+D
c-x c-x x x

we have

2(c-x)=x

thus x=2c/3

thus at equillibrium con. of A= c/3 B= c/3 C=2c/3 and D=2c/3

thue we get equillibrium const. as four

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Dharun ·2009-04-29 20:21:08

ans is 4

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equilibrium

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