hey guys could anyone explain how to find equvalent weight in reaction such as,
example 1-
4KMnO4 + 5HC2O4.H2C2O4.2H2O + 13H2SO4 → 4MnSO4 + 9KHSO4 +20CO2 + 18H2O
the equivalent weight of potassium tetraoxalate crystals are?
a-84.76
b-63.5
c-127
d-158.75
answer given is option b
example 2-
find the equivalent weight of K2Cr2O7 (molecular weight=M)
reaction
K2Cr2O7 + HCl → KCl + CrCl3 + Cl2 + H2O
my question is why do we need to balance the reactions only in some reactions to find the equivalent weight .
Regards,
gp
71In case of redox reactions,to calculate the equivalent weight of a particular compound, you need to calculate the n-factor. But for that you'll have the write up the oxidation and reduction reaction which in turn are used for balancing the reaction.
71In Non redox reaction, the Equivalent weight is simply like E = M/No of H atoms lost (for acids) and so on.
1could you give the method of finding the nfactor after balancing the rxn.
(i can't recall the method of doing it)
thanks,
gp